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10z^2-9z-22=0
a = 10; b = -9; c = -22;
Δ = b2-4ac
Δ = -92-4·10·(-22)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-31}{2*10}=\frac{-22}{20} =-1+1/10 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+31}{2*10}=\frac{40}{20} =2 $
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